Why don't electromagnetic waves interact with each other?












8












$begingroup$


My exact question is that what refers to this phenomenon? I saw also Richards Feynman's video in that he talks about light and says that if we look at something those light waves that come from that thing are not disturbed from any other electromagnetic waves and explains this kind of way that if I can see things clearly, in front of me, although if someone stand in the right of me, can also clearly see any thing in the left of me, our light waves cross each other but the are not disturbed by each other. This is a kinda cool explanation but I don't understand that exactly, because I am not convinced that if those two electromagnetic waves would interact then I couldn't see the thing in front of me clearly






electromagnetic-radiation







share|cite|improve this question











$endgroup$












  • $begingroup$
    Imagine light beams of flashlights were water jets. When you cross two of them, they scatter on each other (interact), so you don't see anything clearly.
    $endgroup$
    – safesphere
    2 days ago










  • $begingroup$
    Please provide a link of the video.
    $endgroup$
    – SRS
    2 days ago










  • $begingroup$
    Link: youtu.be/P1ww1IXRfTA?t=2372
    $endgroup$
    – isarandi
    2 days ago












  • $begingroup$
    I suppose one could say that they do interact in the sense that the electromagnetic field at each point in time and space reachable by both waves is the result of both waves. But due to the underlying principles of field propagation it just so happens that after all the messy interference both waves emerge "unperturbed" as if the interference never had happened ;-). (These principles are discussed in G. Smith's answer.)
    $endgroup$
    – Peter A. Schneider
    2 days ago


















8












$begingroup$


My exact question is that what refers to this phenomenon? I saw also Richards Feynman's video in that he talks about light and says that if we look at something those light waves that come from that thing are not disturbed from any other electromagnetic waves and explains this kind of way that if I can see things clearly, in front of me, although if someone stand in the right of me, can also clearly see any thing in the left of me, our light waves cross each other but the are not disturbed by each other. This is a kinda cool explanation but I don't understand that exactly, because I am not convinced that if those two electromagnetic waves would interact then I couldn't see the thing in front of me clearly






electromagnetic-radiation







share|cite|improve this question











$endgroup$












  • $begingroup$
    Imagine light beams of flashlights were water jets. When you cross two of them, they scatter on each other (interact), so you don't see anything clearly.
    $endgroup$
    – safesphere
    2 days ago










  • $begingroup$
    Please provide a link of the video.
    $endgroup$
    – SRS
    2 days ago










  • $begingroup$
    Link: youtu.be/P1ww1IXRfTA?t=2372
    $endgroup$
    – isarandi
    2 days ago












  • $begingroup$
    I suppose one could say that they do interact in the sense that the electromagnetic field at each point in time and space reachable by both waves is the result of both waves. But due to the underlying principles of field propagation it just so happens that after all the messy interference both waves emerge "unperturbed" as if the interference never had happened ;-). (These principles are discussed in G. Smith's answer.)
    $endgroup$
    – Peter A. Schneider
    2 days ago
















8












8








8


4



$begingroup$


My exact question is that what refers to this phenomenon? I saw also Richards Feynman's video in that he talks about light and says that if we look at something those light waves that come from that thing are not disturbed from any other electromagnetic waves and explains this kind of way that if I can see things clearly, in front of me, although if someone stand in the right of me, can also clearly see any thing in the left of me, our light waves cross each other but the are not disturbed by each other. This is a kinda cool explanation but I don't understand that exactly, because I am not convinced that if those two electromagnetic waves would interact then I couldn't see the thing in front of me clearly






electromagnetic-radiation







share|cite|improve this question











$endgroup$




My exact question is that what refers to this phenomenon? I saw also Richards Feynman's video in that he talks about light and says that if we look at something those light waves that come from that thing are not disturbed from any other electromagnetic waves and explains this kind of way that if I can see things clearly, in front of me, although if someone stand in the right of me, can also clearly see any thing in the left of me, our light waves cross each other but the are not disturbed by each other. This is a kinda cool explanation but I don't understand that exactly, because I am not convinced that if those two electromagnetic waves would interact then I couldn't see the thing in front of me clearly






electromagnetic-radiation




electromagnetic-radiation






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited 2 days ago









SRS

6,781434125




6,781434125










asked Apr 6 at 23:53









Bálint TataiBálint Tatai

27228




27228












  • $begingroup$
    Imagine light beams of flashlights were water jets. When you cross two of them, they scatter on each other (interact), so you don't see anything clearly.
    $endgroup$
    – safesphere
    2 days ago










  • $begingroup$
    Please provide a link of the video.
    $endgroup$
    – SRS
    2 days ago










  • $begingroup$
    Link: youtu.be/P1ww1IXRfTA?t=2372
    $endgroup$
    – isarandi
    2 days ago












  • $begingroup$
    I suppose one could say that they do interact in the sense that the electromagnetic field at each point in time and space reachable by both waves is the result of both waves. But due to the underlying principles of field propagation it just so happens that after all the messy interference both waves emerge "unperturbed" as if the interference never had happened ;-). (These principles are discussed in G. Smith's answer.)
    $endgroup$
    – Peter A. Schneider
    2 days ago




















  • $begingroup$
    Imagine light beams of flashlights were water jets. When you cross two of them, they scatter on each other (interact), so you don't see anything clearly.
    $endgroup$
    – safesphere
    2 days ago










  • $begingroup$
    Please provide a link of the video.
    $endgroup$
    – SRS
    2 days ago










  • $begingroup$
    Link: youtu.be/P1ww1IXRfTA?t=2372
    $endgroup$
    – isarandi
    2 days ago












  • $begingroup$
    I suppose one could say that they do interact in the sense that the electromagnetic field at each point in time and space reachable by both waves is the result of both waves. But due to the underlying principles of field propagation it just so happens that after all the messy interference both waves emerge "unperturbed" as if the interference never had happened ;-). (These principles are discussed in G. Smith's answer.)
    $endgroup$
    – Peter A. Schneider
    2 days ago


















$begingroup$
Imagine light beams of flashlights were water jets. When you cross two of them, they scatter on each other (interact), so you don't see anything clearly.
$endgroup$
– safesphere
2 days ago




$begingroup$
Imagine light beams of flashlights were water jets. When you cross two of them, they scatter on each other (interact), so you don't see anything clearly.
$endgroup$
– safesphere
2 days ago












$begingroup$
Please provide a link of the video.
$endgroup$
– SRS
2 days ago




$begingroup$
Please provide a link of the video.
$endgroup$
– SRS
2 days ago












$begingroup$
Link: youtu.be/P1ww1IXRfTA?t=2372
$endgroup$
– isarandi
2 days ago






$begingroup$
Link: youtu.be/P1ww1IXRfTA?t=2372
$endgroup$
– isarandi
2 days ago














$begingroup$
I suppose one could say that they do interact in the sense that the electromagnetic field at each point in time and space reachable by both waves is the result of both waves. But due to the underlying principles of field propagation it just so happens that after all the messy interference both waves emerge "unperturbed" as if the interference never had happened ;-). (These principles are discussed in G. Smith's answer.)
$endgroup$
– Peter A. Schneider
2 days ago






$begingroup$
I suppose one could say that they do interact in the sense that the electromagnetic field at each point in time and space reachable by both waves is the result of both waves. But due to the underlying principles of field propagation it just so happens that after all the messy interference both waves emerge "unperturbed" as if the interference never had happened ;-). (These principles are discussed in G. Smith's answer.)
$endgroup$
– Peter A. Schneider
2 days ago












1 Answer
1






active

oldest

votes


















20












$begingroup$

Here are three explanations of how to understand “why” electromagnetic waves don’t directly interact electromagnetically with each other, which are all equivalent to each other:




  1. Maxwell’s equations are linear in the electric and magnetic fields, and in their sources, so the superposition of two solutions is also a solution. (For example, in Coulomb’s Law you can just add up the fields of multiple charges.)


  2. Photons do not carry any electric charge and do not have their own electromagnetic field. (Note: By contrast, gluons do carry color charge and do interact with each other.)


  3. The gauge group for electromagnetism is an abelian (i.e., commutative) group. (Gauge groups are something you learn about in more advanced physics courses.)



Notice that I said photons don’t directly interact with each other. They do indirectly interact via virtual electrons and positrons (or other charged particle-antiparticle pairs). Until you get to extremely intense electric and magnetic fields, this is a very tiny effect and was only recently measured.



An even tinier effect, which we will probably never be able to detect, is the gravitational interaction of electromagnetic waves or photons. Physicists believe there would be a gravitational interaction because electromagnetic waves and photons carry energy and momentum, even though photons are massless.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Isn't that "photons are massless at rest"?
    $endgroup$
    – CJ Dennis
    2 days ago






  • 6




    $begingroup$
    @CJDennis Photons can't be at rest.
    $endgroup$
    – SRS
    2 days ago












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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









20












$begingroup$

Here are three explanations of how to understand “why” electromagnetic waves don’t directly interact electromagnetically with each other, which are all equivalent to each other:




  1. Maxwell’s equations are linear in the electric and magnetic fields, and in their sources, so the superposition of two solutions is also a solution. (For example, in Coulomb’s Law you can just add up the fields of multiple charges.)


  2. Photons do not carry any electric charge and do not have their own electromagnetic field. (Note: By contrast, gluons do carry color charge and do interact with each other.)


  3. The gauge group for electromagnetism is an abelian (i.e., commutative) group. (Gauge groups are something you learn about in more advanced physics courses.)



Notice that I said photons don’t directly interact with each other. They do indirectly interact via virtual electrons and positrons (or other charged particle-antiparticle pairs). Until you get to extremely intense electric and magnetic fields, this is a very tiny effect and was only recently measured.



An even tinier effect, which we will probably never be able to detect, is the gravitational interaction of electromagnetic waves or photons. Physicists believe there would be a gravitational interaction because electromagnetic waves and photons carry energy and momentum, even though photons are massless.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Isn't that "photons are massless at rest"?
    $endgroup$
    – CJ Dennis
    2 days ago






  • 6




    $begingroup$
    @CJDennis Photons can't be at rest.
    $endgroup$
    – SRS
    2 days ago
















20












$begingroup$

Here are three explanations of how to understand “why” electromagnetic waves don’t directly interact electromagnetically with each other, which are all equivalent to each other:




  1. Maxwell’s equations are linear in the electric and magnetic fields, and in their sources, so the superposition of two solutions is also a solution. (For example, in Coulomb’s Law you can just add up the fields of multiple charges.)


  2. Photons do not carry any electric charge and do not have their own electromagnetic field. (Note: By contrast, gluons do carry color charge and do interact with each other.)


  3. The gauge group for electromagnetism is an abelian (i.e., commutative) group. (Gauge groups are something you learn about in more advanced physics courses.)



Notice that I said photons don’t directly interact with each other. They do indirectly interact via virtual electrons and positrons (or other charged particle-antiparticle pairs). Until you get to extremely intense electric and magnetic fields, this is a very tiny effect and was only recently measured.



An even tinier effect, which we will probably never be able to detect, is the gravitational interaction of electromagnetic waves or photons. Physicists believe there would be a gravitational interaction because electromagnetic waves and photons carry energy and momentum, even though photons are massless.






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Isn't that "photons are massless at rest"?
    $endgroup$
    – CJ Dennis
    2 days ago






  • 6




    $begingroup$
    @CJDennis Photons can't be at rest.
    $endgroup$
    – SRS
    2 days ago














20












20








20





$begingroup$

Here are three explanations of how to understand “why” electromagnetic waves don’t directly interact electromagnetically with each other, which are all equivalent to each other:




  1. Maxwell’s equations are linear in the electric and magnetic fields, and in their sources, so the superposition of two solutions is also a solution. (For example, in Coulomb’s Law you can just add up the fields of multiple charges.)


  2. Photons do not carry any electric charge and do not have their own electromagnetic field. (Note: By contrast, gluons do carry color charge and do interact with each other.)


  3. The gauge group for electromagnetism is an abelian (i.e., commutative) group. (Gauge groups are something you learn about in more advanced physics courses.)



Notice that I said photons don’t directly interact with each other. They do indirectly interact via virtual electrons and positrons (or other charged particle-antiparticle pairs). Until you get to extremely intense electric and magnetic fields, this is a very tiny effect and was only recently measured.



An even tinier effect, which we will probably never be able to detect, is the gravitational interaction of electromagnetic waves or photons. Physicists believe there would be a gravitational interaction because electromagnetic waves and photons carry energy and momentum, even though photons are massless.






share|cite|improve this answer











$endgroup$



Here are three explanations of how to understand “why” electromagnetic waves don’t directly interact electromagnetically with each other, which are all equivalent to each other:




  1. Maxwell’s equations are linear in the electric and magnetic fields, and in their sources, so the superposition of two solutions is also a solution. (For example, in Coulomb’s Law you can just add up the fields of multiple charges.)


  2. Photons do not carry any electric charge and do not have their own electromagnetic field. (Note: By contrast, gluons do carry color charge and do interact with each other.)


  3. The gauge group for electromagnetism is an abelian (i.e., commutative) group. (Gauge groups are something you learn about in more advanced physics courses.)



Notice that I said photons don’t directly interact with each other. They do indirectly interact via virtual electrons and positrons (or other charged particle-antiparticle pairs). Until you get to extremely intense electric and magnetic fields, this is a very tiny effect and was only recently measured.



An even tinier effect, which we will probably never be able to detect, is the gravitational interaction of electromagnetic waves or photons. Physicists believe there would be a gravitational interaction because electromagnetic waves and photons carry energy and momentum, even though photons are massless.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Apr 7 at 0:53

























answered Apr 7 at 0:26









G. SmithG. Smith

10.8k11431




10.8k11431












  • $begingroup$
    Isn't that "photons are massless at rest"?
    $endgroup$
    – CJ Dennis
    2 days ago






  • 6




    $begingroup$
    @CJDennis Photons can't be at rest.
    $endgroup$
    – SRS
    2 days ago


















  • $begingroup$
    Isn't that "photons are massless at rest"?
    $endgroup$
    – CJ Dennis
    2 days ago






  • 6




    $begingroup$
    @CJDennis Photons can't be at rest.
    $endgroup$
    – SRS
    2 days ago
















$begingroup$
Isn't that "photons are massless at rest"?
$endgroup$
– CJ Dennis
2 days ago




$begingroup$
Isn't that "photons are massless at rest"?
$endgroup$
– CJ Dennis
2 days ago




6




6




$begingroup$
@CJDennis Photons can't be at rest.
$endgroup$
– SRS
2 days ago




$begingroup$
@CJDennis Photons can't be at rest.
$endgroup$
– SRS
2 days ago


















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