QGIS: use geometry from different layer in symbology expression
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 7 hours ago
Matthias Kuhn
18.9k14890
asked 7 hours ago
CaptainAhabCaptainAhab
656
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 7 hours ago
Matthias Kuhn
18.9k14890
asked 7 hours ago
CaptainAhabCaptainAhab
656
add a comment |
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
edited 7 hours ago
Matthias Kuhn
18.9k14890
asked 7 hours ago
CaptainAhabCaptainAhab
656
I have a project with multiple layers.
The purple dots are from a pointfile with the symbology-expression:
z($geometry)> '14.5'. (so it only displays a purple dot when the Z-value is more than 14.5m).
I have a second layer with polygons, visible as the partly-transparent arc-area in red.
The next step i want to make in my project is to:
have the purple dots appear only if:
z($geometry)>'14.5' AND
the x-y of that spot is within the geographical extent of the polygon from the second layer
What step do i have to take to get this done.
qgis symbology z-value
qgis symbology z-value
edited 7 hours ago
Matthias Kuhn
18.9k14890
asked 7 hours ago
CaptainAhabCaptainAhab
656
edited 7 hours ago
Matthias Kuhn
18.9k14890
asked 7 hours ago
CaptainAhabCaptainAhab
656
edited 7 hours ago
Matthias Kuhn
18.9k14890
edited 7 hours ago
Matthias Kuhn
18.9k14890
edited 7 hours ago
Matthias Kuhn
18.9k14890
18.9k14890
asked 7 hours ago
CaptainAhabCaptainAhab
656
asked 7 hours ago
CaptainAhabCaptainAhab
656
asked 7 hours ago
CaptainAhabCaptainAhab
656
656
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 6 hours ago
VitruviusVitruvius
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
4 hours ago
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "79"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fgis.stackexchange.com%2fquestions%2f314167%2fqgis-use-geometry-from-different-layer-in-symbology-expression%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 6 hours ago
VitruviusVitruvius
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
4 hours ago
add a comment |
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 6 hours ago
VitruviusVitruvius
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
4 hours ago
add a comment |
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 6 hours ago
VitruviusVitruvius
439210
Your question is very similar to what I've done here recently.
I used expression:
if(
within($geometry,geometry(get_feature(layer,attribute,value))),
result_when_true,
result_when_false
)
In your case step 1: filter data table by
z($geometry)> '14.5'
step 2: paste expression in point symbology layer (see gif to find where)
if(
within($geometry,geometry(get_feature('your_polygon_layer_name','the_layers_field','feature_data'))),
1,
0
)
You can use the same expression for labels but must change 1 and 0 values to "label_field_name" and to null.
That's it.
answered 6 hours ago
VitruviusVitruvius
439210
edited 5 hours ago
answered 6 hours ago
VitruviusVitruvius
439210
answered 6 hours ago
VitruviusVitruvius
439210
answered 6 hours ago
VitruviusVitruvius
439210
439210
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
4 hours ago
add a comment |
Good answer! Would it work to drop the if-part completely and just usewithin(...)?
– Matthias Kuhn
4 hours ago
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
4 hours ago
Good answer! Would it work to drop the if-part completely and just use
within(...)?– Matthias Kuhn
4 hours ago
add a comment |
Thanks for contributing an answer to Geographic Information Systems Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fgis.stackexchange.com%2fquestions%2f314167%2fqgis-use-geometry-from-different-layer-in-symbology-expression%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
