What is the behavior of solc with optimizer disabled?
When enabling the optimizer the documentation of solc tells you that you can choose between optimizing the gas cost at deployment or the gas cost at execution by setting the runs parameter.
But what is the default behavior when the optimizer is disabled? Will the compiled bytecode lead to high gas cost of deployment AND high gas cost fo execution, or can we assume that it leads by default to high gas cost of deployment but low for gas cost of execution?
solidity truffle solc
edited 8 hours ago
Rick Park
1,109214
asked 9 hours ago
junizjuniz
325
add a comment |
When enabling the optimizer the documentation of solc tells you that you can choose between optimizing the gas cost at deployment or the gas cost at execution by setting the runs parameter.
But what is the default behavior when the optimizer is disabled? Will the compiled bytecode lead to high gas cost of deployment AND high gas cost fo execution, or can we assume that it leads by default to high gas cost of deployment but low for gas cost of execution?
solidity truffle solc
edited 8 hours ago
Rick Park
1,109214
asked 9 hours ago
junizjuniz
325
It's probably equivalent tooptimize=falseANDruns=0, so you can do the math from here ((i.e., if increasingrunsreduces execution gas cost, then decreasingrunswill enlarge execution gas cost).
– goodvibration
9 hours ago
add a comment |
When enabling the optimizer the documentation of solc tells you that you can choose between optimizing the gas cost at deployment or the gas cost at execution by setting the runs parameter.
But what is the default behavior when the optimizer is disabled? Will the compiled bytecode lead to high gas cost of deployment AND high gas cost fo execution, or can we assume that it leads by default to high gas cost of deployment but low for gas cost of execution?
solidity truffle solc
edited 8 hours ago
Rick Park
1,109214
asked 9 hours ago
junizjuniz
325
When enabling the optimizer the documentation of solc tells you that you can choose between optimizing the gas cost at deployment or the gas cost at execution by setting the runs parameter.
But what is the default behavior when the optimizer is disabled? Will the compiled bytecode lead to high gas cost of deployment AND high gas cost fo execution, or can we assume that it leads by default to high gas cost of deployment but low for gas cost of execution?
solidity truffle solc
solidity truffle solc
edited 8 hours ago
Rick Park
1,109214
asked 9 hours ago
junizjuniz
325
edited 8 hours ago
Rick Park
1,109214
asked 9 hours ago
junizjuniz
325
edited 8 hours ago
Rick Park
1,109214
edited 8 hours ago
Rick Park
1,109214
edited 8 hours ago
Rick Park
1,109214
1,109214
asked 9 hours ago
junizjuniz
325
asked 9 hours ago
junizjuniz
325
asked 9 hours ago
junizjuniz
325
325
It's probably equivalent tooptimize=falseANDruns=0, so you can do the math from here ((i.e., if increasingrunsreduces execution gas cost, then decreasingrunswill enlarge execution gas cost).
– goodvibration
9 hours ago
add a comment |
It's probably equivalent tooptimize=falseANDruns=0, so you can do the math from here ((i.e., if increasingrunsreduces execution gas cost, then decreasingrunswill enlarge execution gas cost).
– goodvibration
9 hours ago
It's probably equivalent to
optimize=false AND runs=0, so you can do the math from here ((i.e., if increasing runs reduces execution gas cost, then decreasing runs will enlarge execution gas cost).– goodvibration
9 hours ago
It's probably equivalent to
optimize=false AND runs=0, so you can do the math from here ((i.e., if increasing runs reduces execution gas cost, then decreasing runs will enlarge execution gas cost).– goodvibration
9 hours ago
add a comment |
1 Answer
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The default is “I do not care about gas, on deployment or when running. Just give me a bytecode easy to debug.”
As a matter of fact the code size shall be bigger than the minimum and the execution cost shall be bigger than the minimum, but the mapping from source code to bytecode shall be as detailed and clear as it can be.
“Runs” can be interpreted as the expected number of runs of the deployed code in the whole life of the contract to be optimized.
If you specify Runs=10 it means that any optimization that make it globally less costly to deploy and run ten times the code are allowed. And this can be very different than optimize one deploy and 1000 executions!
answered 8 hours ago
Rick ParkRick Park
1,109214
add a comment |
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1 Answer
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The default is “I do not care about gas, on deployment or when running. Just give me a bytecode easy to debug.”
As a matter of fact the code size shall be bigger than the minimum and the execution cost shall be bigger than the minimum, but the mapping from source code to bytecode shall be as detailed and clear as it can be.
“Runs” can be interpreted as the expected number of runs of the deployed code in the whole life of the contract to be optimized.
If you specify Runs=10 it means that any optimization that make it globally less costly to deploy and run ten times the code are allowed. And this can be very different than optimize one deploy and 1000 executions!
answered 8 hours ago
Rick ParkRick Park
1,109214
add a comment |
The default is “I do not care about gas, on deployment or when running. Just give me a bytecode easy to debug.”
As a matter of fact the code size shall be bigger than the minimum and the execution cost shall be bigger than the minimum, but the mapping from source code to bytecode shall be as detailed and clear as it can be.
“Runs” can be interpreted as the expected number of runs of the deployed code in the whole life of the contract to be optimized.
If you specify Runs=10 it means that any optimization that make it globally less costly to deploy and run ten times the code are allowed. And this can be very different than optimize one deploy and 1000 executions!
answered 8 hours ago
Rick ParkRick Park
1,109214
add a comment |
The default is “I do not care about gas, on deployment or when running. Just give me a bytecode easy to debug.”
As a matter of fact the code size shall be bigger than the minimum and the execution cost shall be bigger than the minimum, but the mapping from source code to bytecode shall be as detailed and clear as it can be.
“Runs” can be interpreted as the expected number of runs of the deployed code in the whole life of the contract to be optimized.
If you specify Runs=10 it means that any optimization that make it globally less costly to deploy and run ten times the code are allowed. And this can be very different than optimize one deploy and 1000 executions!
answered 8 hours ago
Rick ParkRick Park
1,109214
The default is “I do not care about gas, on deployment or when running. Just give me a bytecode easy to debug.”
As a matter of fact the code size shall be bigger than the minimum and the execution cost shall be bigger than the minimum, but the mapping from source code to bytecode shall be as detailed and clear as it can be.
“Runs” can be interpreted as the expected number of runs of the deployed code in the whole life of the contract to be optimized.
If you specify Runs=10 it means that any optimization that make it globally less costly to deploy and run ten times the code are allowed. And this can be very different than optimize one deploy and 1000 executions!
answered 8 hours ago
Rick ParkRick Park
1,109214
answered 8 hours ago
Rick ParkRick Park
1,109214
answered 8 hours ago
Rick ParkRick Park
1,109214
answered 8 hours ago
Rick ParkRick Park
1,109214
1,109214
add a comment |
add a comment |
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It's probably equivalent to
optimize=falseANDruns=0, so you can do the math from here ((i.e., if increasingrunsreduces execution gas cost, then decreasingrunswill enlarge execution gas cost).– goodvibration
9 hours ago