Selecting elements from lists based on string pattern












1












$begingroup$


I have a list:



lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


I would like to select list items that have first elements that end in the string "bc" to give:



res = {{1,2},{5,6}}


This is a variant on this question which has to do with strings only. Thank you as always for suggestions.










share|improve this question









$endgroup$

















    1












    $begingroup$


    I have a list:



    lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


    I would like to select list items that have first elements that end in the string "bc" to give:



    res = {{1,2},{5,6}}


    This is a variant on this question which has to do with strings only. Thank you as always for suggestions.










    share|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      I have a list:



      lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


      I would like to select list items that have first elements that end in the string "bc" to give:



      res = {{1,2},{5,6}}


      This is a variant on this question which has to do with strings only. Thank you as always for suggestions.










      share|improve this question









      $endgroup$




      I have a list:



      lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}}


      I would like to select list items that have first elements that end in the string "bc" to give:



      res = {{1,2},{5,6}}


      This is a variant on this question which has to do with strings only. Thank you as always for suggestions.







      list-manipulation string-manipulation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 3 hours ago









      Suite401Suite401

      988312




      988312






















          3 Answers
          3






          active

          oldest

          votes


















          2












          $begingroup$

          Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



          {{1, 2}, {5, 6}}




          Also



          f[{_String?(StringEndsQ["bc"]), x__}] := {x}
          f[_] := Sequence
          f /@ lis



          {{1, 2}, {5, 6}}







          share|improve this answer









          $endgroup$





















            1












            $begingroup$

            This uses string matching on the first element of each sublist and then discards the first element from the matches.



            lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
            Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]

            (* {{1, 2}, {5, 6}} *)


            You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






            share|improve this answer









            $endgroup$





















              1












              $begingroup$

              lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


              Using Cases



              Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
              Infinity]

              (* {{1, 2}, {5, 6}} *)


              or



              Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]

              (* {{1, 2}, {5, 6}} *)


              Or using Select



              Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]

              (* {{1, 2}, {5, 6}} *)


              Or using DeleteCases



              Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
              Infinity]

              (* {{1, 2}, {5, 6}} *)





              share|improve this answer









              $endgroup$













                Your Answer





                StackExchange.ifUsing("editor", function () {
                return StackExchange.using("mathjaxEditing", function () {
                StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
                StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
                });
                });
                }, "mathjax-editing");

                StackExchange.ready(function() {
                var channelOptions = {
                tags: "".split(" "),
                id: "387"
                };
                initTagRenderer("".split(" "), "".split(" "), channelOptions);

                StackExchange.using("externalEditor", function() {
                // Have to fire editor after snippets, if snippets enabled
                if (StackExchange.settings.snippets.snippetsEnabled) {
                StackExchange.using("snippets", function() {
                createEditor();
                });
                }
                else {
                createEditor();
                }
                });

                function createEditor() {
                StackExchange.prepareEditor({
                heartbeatType: 'answer',
                autoActivateHeartbeat: false,
                convertImagesToLinks: false,
                noModals: true,
                showLowRepImageUploadWarning: true,
                reputationToPostImages: null,
                bindNavPrevention: true,
                postfix: "",
                imageUploader: {
                brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
                contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
                allowUrls: true
                },
                onDemand: true,
                discardSelector: ".discard-answer"
                ,immediatelyShowMarkdownHelp:true
                });


                }
                });














                draft saved

                draft discarded


















                StackExchange.ready(
                function () {
                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f190698%2fselecting-elements-from-lists-based-on-string-pattern%23new-answer', 'question_page');
                }
                );

                Post as a guest















                Required, but never shown

























                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                2












                $begingroup$

                Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                {{1, 2}, {5, 6}}




                Also



                f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                f[_] := Sequence
                f /@ lis



                {{1, 2}, {5, 6}}







                share|improve this answer









                $endgroup$


















                  2












                  $begingroup$

                  Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                  {{1, 2}, {5, 6}}




                  Also



                  f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                  f[_] := Sequence
                  f /@ lis



                  {{1, 2}, {5, 6}}







                  share|improve this answer









                  $endgroup$
















                    2












                    2








                    2





                    $begingroup$

                    Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                    {{1, 2}, {5, 6}}




                    Also



                    f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                    f[_] := Sequence
                    f /@ lis



                    {{1, 2}, {5, 6}}







                    share|improve this answer









                    $endgroup$



                    Pick[lis[[All, 2 ;;]], StringEndsQ[lis[[All, 1]], "bc"]]



                    {{1, 2}, {5, 6}}




                    Also



                    f[{_String?(StringEndsQ["bc"]), x__}] := {x}
                    f[_] := Sequence
                    f /@ lis



                    {{1, 2}, {5, 6}}








                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered 32 mins ago









                    kglrkglr

                    181k10200413




                    181k10200413























                        1












                        $begingroup$

                        This uses string matching on the first element of each sublist and then discards the first element from the matches.



                        lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                        Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]

                        (* {{1, 2}, {5, 6}} *)


                        You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






                        share|improve this answer









                        $endgroup$


















                          1












                          $begingroup$

                          This uses string matching on the first element of each sublist and then discards the first element from the matches.



                          lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                          Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]

                          (* {{1, 2}, {5, 6}} *)


                          You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






                          share|improve this answer









                          $endgroup$
















                            1












                            1








                            1





                            $begingroup$

                            This uses string matching on the first element of each sublist and then discards the first element from the matches.



                            lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                            Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]

                            (* {{1, 2}, {5, 6}} *)


                            You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.






                            share|improve this answer









                            $endgroup$



                            This uses string matching on the first element of each sublist and then discards the first element from the matches.



                            lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};
                            Rest/@Select[lis,StringMatchQ[First[#],RegularExpression["\w*bc"]]&]

                            (* {{1, 2}, {5, 6}} *)


                            You may need to adjust the pattern given to RegularExpression if your strings do not all begin with word characters.







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 2 hours ago









                            BillBill

                            5,62569




                            5,62569























                                1












                                $begingroup$

                                lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                Using Cases



                                Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                Infinity]

                                (* {{1, 2}, {5, 6}} *)


                                or



                                Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]

                                (* {{1, 2}, {5, 6}} *)


                                Or using Select



                                Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]

                                (* {{1, 2}, {5, 6}} *)


                                Or using DeleteCases



                                Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                Infinity]

                                (* {{1, 2}, {5, 6}} *)





                                share|improve this answer









                                $endgroup$


















                                  1












                                  $begingroup$

                                  lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                  Using Cases



                                  Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                  Infinity]

                                  (* {{1, 2}, {5, 6}} *)


                                  or



                                  Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]

                                  (* {{1, 2}, {5, 6}} *)


                                  Or using Select



                                  Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]

                                  (* {{1, 2}, {5, 6}} *)


                                  Or using DeleteCases



                                  Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                  Infinity]

                                  (* {{1, 2}, {5, 6}} *)





                                  share|improve this answer









                                  $endgroup$
















                                    1












                                    1








                                    1





                                    $begingroup$

                                    lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                    Using Cases



                                    Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                    Infinity]

                                    (* {{1, 2}, {5, 6}} *)


                                    or



                                    Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]

                                    (* {{1, 2}, {5, 6}} *)


                                    Or using Select



                                    Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]

                                    (* {{1, 2}, {5, 6}} *)


                                    Or using DeleteCases



                                    Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                    Infinity]

                                    (* {{1, 2}, {5, 6}} *)





                                    share|improve this answer









                                    $endgroup$



                                    lis = {{"abc", 1, 2}, {"cde", 3, 4}, {"fgbc", 5, 6}};


                                    Using Cases



                                    Cases[lis, {_?(StringTake[#, -2] == "bc" &), x_, y_} :> {x, y}, 
                                    Infinity]

                                    (* {{1, 2}, {5, 6}} *)


                                    or



                                    Rest /@ Cases[lis, {_?(StringTake[#, -2] == "bc" &), __}, Infinity]

                                    (* {{1, 2}, {5, 6}} *)


                                    Or using Select



                                    Rest /@ Select[lis, StringTake[#[[1]], -2] == "bc" &]

                                    (* {{1, 2}, {5, 6}} *)


                                    Or using DeleteCases



                                    Rest /@ DeleteCases[lis, {_?(StringTake[#, -2] != "bc" &), __}, 
                                    Infinity]

                                    (* {{1, 2}, {5, 6}} *)






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 2 hours ago









                                    Bob HanlonBob Hanlon

                                    59.5k33596




                                    59.5k33596






























                                        draft saved

                                        draft discarded




















































                                        Thanks for contributing an answer to Mathematica Stack Exchange!


                                        • Please be sure to answer the question. Provide details and share your research!

                                        But avoid



                                        • Asking for help, clarification, or responding to other answers.

                                        • Making statements based on opinion; back them up with references or personal experience.


                                        Use MathJax to format equations. MathJax reference.


                                        To learn more, see our tips on writing great answers.




                                        draft saved


                                        draft discarded














                                        StackExchange.ready(
                                        function () {
                                        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f190698%2fselecting-elements-from-lists-based-on-string-pattern%23new-answer', 'question_page');
                                        }
                                        );

                                        Post as a guest















                                        Required, but never shown





















































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown

































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown







                                        Popular posts from this blog

                                        Statuo de Libereco

                                        Tanganjiko

                                        Liste der Baudenkmäler in Enneberg